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给出四个数字,要求,在其间添加运算符和括号,使得计算结果等于24。& U4 O1 w4 v4 n9 W S
4 h8 q% F2 P" a" r! L3 M. s" _括号的放置即为决定哪几个数先进行计算。所以,我们先确定首先进行计算的两个相邻的数,计算完成后,就相当于剩下三个数字,仍需要在它们之间添加符号;然后再决定在这三个数中哪两个相邻的数先计算。由此,我们就成功解决了数字的运算次序问题,此时不需要再考虑不同运算符号的优先级问题,因为括号的优先级高于加减乘除。7 s4 N! Q# n' v5 z7 e
% U& x3 v+ N8 P# [, C% a: ^% P, _通过循环,我们可以得到第一第二第三次计算的运算符,再通过计算,就可以得出和,若和等于24,即为所求解。
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2 h8 a# i& c1 G在输出格式中,由于括号的放置共六种情况,故根据计算先后顺序的不同,输出时在不同地方放置括号;
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) M m7 c0 M9 K4 p3 ^以下是java源码:( d% l" X6 ] i. r6 q; l
- import java.awt.*;
7 d5 s' ?3 g8 h/ A - import javax.swing.*; e# c% x$ d- _4 a4 e6 E
- import java.awt.event.*;% i* }8 H$ ^* }, H4 o1 V: y. `' Y' ^
- import java.util.*;0 G, n! g4 d8 ]" u
- import javax.swing.JOptionPane;% I# t- R% q; l O0 D- \: V
-
0 w# K/ Q9 d' J - public class TwentyFourPoke_Game extends JFrame! \# w8 i6 e7 \5 Z. d
- {
& b2 C0 R! `1 i2 D8 C - private JButton jbsolution = new JButton("Find a Solution");3 [" _ h; k: A6 ~
- private JButton jbrefresh = new JButton("Refresh");
8 B9 S2 f; b& m- k4 [6 x - private JButton jbverify = new JButton("Verify");
, x7 N" ~9 h2 ]4 |( m -
0 h: n# X. J7 @9 q, W7 @ I - private JLabel jlmessage = new JLabel("Enter an expression:");' N. V1 m. u2 c% B# Q
- ; ]' d, u* C7 k8 r, u
- private JTextField jtsolution = new JTextField();$ g) p% u! j+ K) S$ H$ v. q
- private JTextField jtexpression = new JTextField();
- C: u H6 Q# V* s8 G4 D -
5 I& w) c" B0 g- B( F v - private ImagePanel pp = new ImagePanel();
( t& \. y: ]3 r# i2 c: ` - 4 A/ T9 s8 q1 q7 y5 P* [- U! {$ C
- private int[] card = new int[4];7 i# w0 \- T# N
- private double[] bcard = new double[4];' ^: \# A6 v) r) p' ~; {# G
- ' T: h2 r8 A$ H; Y x
- private double sum;: h4 b0 G, F5 F+ C2 f
- private double[] temp1 = new double[3];* [) C6 e5 Z5 `' q6 M. G, h
- private double[] temp2 = new double[2];- R; d7 s# `: l9 P; v1 O
- private char[] sign = {'+','-','*','/'};
& x" i! y; x( r9 b/ m$ |: K - ' w" W, t( r6 ~: P+ O
- & g( k: Y; K2 {% `/ P( u' q
- public TwentyFourPoke_Game()
4 w& p4 U* @ R6 _# v" @1 t - {+ Z3 S: B; e" R, B
- JPanel p1 = new JPanel(new GridLayout(1,3));* `# {. }/ C# o4 f E3 A* a
- p1.add(jbsolution);
- g j. Q% h8 T5 L - p1.add(jtsolution);" F8 B, c2 m0 [
- p1.add(jbrefresh);
4 N/ D( G8 u' |$ v0 U9 U5 L - JPanel p3 = new JPanel(new GridLayout(1,3));
9 A' d6 `" J" [: I1 k1 p - p3.add(jlmessage);0 O' \0 e, Q% U- h# ~3 e- A
- p3.add(jtexpression);0 A4 v% C& {5 g1 A
- p3.add(jbverify);8 }7 m; e: o" _
-
2 M6 H! F" L/ v% N - add(p1,BorderLayout.NORTH);
$ g9 z6 {$ z( Q) `* I7 p - add(pp,BorderLayout.CENTER);
7 E" v1 u$ h8 G - add(p3,BorderLayout.SOUTH);) C9 J% p% A6 f8 m! Q
-
9 f, O% @( r- {. L$ r. }( z0 N - ButtonListener listener = new ButtonListener();7 @5 J3 j$ Y& p- b8 a4 d
- jbsolution.addActionListener(listener);: B R. o i) \( z
- jbrefresh.addActionListener(listener);
, @8 D4 d0 f/ q3 }5 U+ ` - jbverify.addActionListener(listener);: e4 H/ t4 F2 s
- }1 ?4 ?3 D. l" w* B7 a
-
% c `4 p$ ?$ F. n% O9 V; N - class ButtonListener implements ActionListener& R& E S& F0 P5 H! m# U
- {
# w, G3 W7 [: C3 F - public void actionPerformed(ActionEvent e)
2 |5 ^8 [1 [: _& S/ T: S" c: B: t5 f2 J - {
- X' y- | G; c) ?1 r( q# X: a - if(e.getSource() == jbsolution), D* \! c3 ]6 h# i
- {! w( h5 u5 \1 C1 `/ U% I
- for(int i = 0;i < 4;i++)2 g! q z/ g+ K
- {" o; \$ |6 _$ B3 ]) I) J+ o
- bcard[i] = (double)card[i] % 13;
/ c- h, w4 U$ a - if(card[i] % 13 == 0)2 t7 }+ ?# a. b7 X
- bcard[i] = 13;
* q# w' ?4 N8 ]- B! J5 m" e - }$ P' h8 i3 r, z. F6 h
- search();4 ~% V0 Y# J" N+ ?, F( E5 T
- }
, e" O) g+ }* \, ?$ F4 S - else if(e.getSource() == jbrefresh)
8 a3 f, ~: s# { - {
; T3 w* {- w0 s- |* N$ b3 v - pp.sshow();! \0 s$ z$ Z5 _, ]9 H: H; A2 E
- 0 `+ C2 V7 O D$ z8 M1 W
- }3 d* a' e2 `4 P* }1 b; G
- else if(e.getSource() == jbverify)
) z W1 ? i* Q - {8 i6 M! Y! v" g, X# T& S
- String expression = jtexpression.getText();
, {8 n# N3 Y% |% D1 [ - int result = evaluateExpression(expression);8 Y+ A# h7 b9 e+ Y* g
- if(result == 24)+ ?( F# S+ Q) n( R4 b C
- {
7 [) B+ _1 E, T2 O+ F# j8 @2 w - JOptionPane.showMessageDialog(null,"恭喜你!你答对了!","消息框",JOptionPane.INFORMATION_MESSAGE);
! e) J! q% q6 { - }* C6 G0 S2 K; d
- else
8 Q4 X, D* z3 i4 R: S* x - {
^" ?' ^3 k; c( _' V - JOptionPane.showMessageDialog(null,"抱歉!请再次尝试。","消息框",JOptionPane.INFORMATION_MESSAGE);
+ m% V+ Q) ?5 F) Y+ W/ C* `5 R - }
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- } R9 L# o& E6 j# h4 p3 H
- }
0 y1 B" G5 z, s, \' t -
) s: u# [: e$ M0 D7 a( e; z7 X - public static double calcute(double a,double b,char c)4 h, d0 N* d: j0 P8 `
- {
6 p/ \1 D! X* g& h3 K, `2 V - if(c == '+')' A ^* O) Y/ G i1 Q
- return a+b;
" ]$ n6 r! w. c- _; |6 J - else if(c == '-')
8 S2 F: O: q; L5 p2 [, `! A - return a-b;
7 i( w7 A) h, s% l: e7 r) k6 L - else if(c == '*')
5 @1 L3 V6 V0 F- [ - return a*b;
. @( \" ^! V- A% Q! z" i- M - else if(c == '/' && b != 0)' s0 { D! U% m1 ?- O
- return a/b;! ^' u3 S1 o% ^9 ^
- else7 i; h: ~9 S2 _6 d9 a
- return -1;
) c9 w; Q$ v, g/ x- j" k* j# R. b - }( }0 w2 J! E0 y5 \( j8 T; c" `
- ( o# D6 |# q3 Y- F6 z' A
- public void search()
' @) U4 x* j) A% V/ [9 ? - {' I# Q5 f* ?# h+ E# c, S
- boolean judge = false;
7 U( f9 y2 `+ I0 A/ Z; a - for(int i=0;i<4;i++)4 Y3 _; P! n6 L# N2 x4 O: o7 g" Q
- //第一次放置的符号
8 _7 n8 A b; C. _7 U - {
* }! a. ?0 D K - for(int j=0;j<4;j++)
) Z1 [( }1 C' u - //第二次放置的符号
+ Z- }6 B4 ]& {/ I$ z1 N$ L - {0 \4 ^9 t9 y# G! G! j
- for(int k=0;k<4;k++)& b! s+ [! w7 g' s
- //第三次放置的符号% A i. \$ ?* \: Y/ q" S6 g% \
- {/ {7 v; M& |6 m3 e9 Q) X
- for(int m=0;m<3;m++)* A9 B0 @. x7 g5 K8 c% s
- //首先计算的两个相邻数字,共有3种情况,相当于括号的作用* A. v& e; T# t- j
- {
% c0 |# Q8 z. A- \9 v6 R - if(bcard[m+1]==0 && sign[i]=='/') break;4 P/ ^5 T5 t: B0 K
- temp1[m]=calcute(bcard[m],bcard[m+1],sign[i]);
" u: k5 e- V3 q( y, ] - temp1[(m+1)%3]=bcard[(m+2)%4];
[7 Y1 c5 N: W; h/ W - temp1[(m+2)%3]=bcard[(m+3)%4];! ~& c* S' j- E/ g
- //先确定首先计算的两个数字,计算完成相当于剩下三个数,按顺序储存在temp数组中, r$ f$ j; V" n: L
- for(int n=0;n<2;n++)" ^9 E X# W+ [# F& g: w8 _# n
- //三个数字选出先计算的两个相邻数字,两种情况,相当于第二个括号0 J- \# j3 H( I. h
- {
: [- \; x4 S, z' P - if(temp1[n+1]==0 && sign[j]=='/') break;, p- z6 e( x9 ~7 z- S @+ g
- temp2[n]=calcute(temp1[n],temp1[n+1],sign[j]);
) W5 H: N+ a5 _9 E - temp2[(n+1)%2]=temp1[(n+2)%3];: |* T" c, c# y, h5 ]. |
- //先确定首先计算的两个数字,计算完成相当于剩下两个数,按顺序储存在temp数组中
4 c5 Z+ \5 H: Q& O - if(temp2[1]==0 && sign[k]=='/') break;
$ R+ t, ]* O- M5 U7 f x( U: U9 ` - sum=calcute(temp2[0],temp2[1],sign[k]);. Z+ J& v( |. L: T6 {1 ~
- //计算和/ _6 P1 x1 G' `! S. n& D
- if(sum==24)# t' Z! l+ w8 ]" C6 ]# G. b
- //若和为24
6 Q" D" k4 V3 j- g1 c8 F - {
, ?4 J, y, ?# W/ v - judge=true;& M8 {* C A2 z" |3 @
- //判断符为1,表示已求得解3 Z* P4 j- R& r. _0 D& v7 j
- if(m==0 && n==0)
7 ^6 e6 \! Q4 p/ [ - {- M1 u: G, q' e& F+ u
- String sss ="(("+(int)bcard[0]+sign[i]+(int)bcard[1]+")"+sign[j]+(int)bcard[2]+")"+sign[k]+(int)bcard[3]+"="+(int)sum;9 J6 p/ U1 T) \ A% f0 L
- jtsolution.setText(sss);
% J5 t5 L ]6 |$ x. y4 ? - return ;/ U* i! w' Z, S+ M' W$ ]( U/ w
- }4 o, |! Y% M. Y1 \0 L. M5 [# p
- else if(m==0 && n==1) d: X( J/ l1 V! ]( [6 _, U
- {
2 V8 H- E% ^$ O - String sss ="("+(int)bcard[0]+sign[i]+(int)bcard[1]+")"+sign[k]+"("+(int)bcard[2]+sign[j]+(int)bcard[3]+")="+(int)sum;
* f' N4 n3 h# j& Y: | - jtsolution.setText(sss);1 r& t. f' A7 H9 Z6 L! ^7 f g
- return ;* x5 {2 V2 u/ L1 k; N; _: U
- }
$ y/ I$ q2 R7 B b- Q; G: X - else if(m==1 && n==0)
1 i* E+ J `& }, H& }, R6 h @ - {
5 N6 k5 v# |5 R9 I6 X( [3 f- \" j - String sss ="("+(int)bcard[0]+sign[j]+"("+(int)bcard[1]+sign[i]+(int)bcard[2]+"))"+sign[k]+(int)bcard[3]+"="+(int)sum;
- H: l+ T$ k1 b. j, W - jtsolution.setText(sss);" g( G. c( O2 v! |
- return ;( m1 K, R8 f) l! ?* \
- }
+ g) d5 l8 Y+ O. ^" z) B* k n+ M - else if(m==2 && n==0)' U9 X& G5 [0 b2 T; ^
- {& W6 J+ J7 b3 X# J0 z+ p3 [
- String sss ="("+(int)bcard[0]+sign[j]+(int)bcard[1]+")"+sign[k]+"("+(int)bcard[2]+sign[i]+(int)bcard[3]+")="+(int)sum;/ H7 W. Z- E3 E4 G% m9 X }: O0 e
- jtsolution.setText(sss);
' l4 Y! B( }% i3 R- [. o+ R* M - return ;: ^, Q5 B; @1 u% x# r- c% x
- }
& L! U1 f( G6 n$ |+ t- z( b" C - else if(m==2 && n==0)) s( }9 t5 c' [4 Z9 |5 q9 V
- {2 j6 Y# }" R! p5 x
- String sss =(int)bcard[0]+sign[k]+"("+(int)bcard[1]+sign[j]+"("+(int)bcard[2]+sign[i]+(int)bcard[3]+"))="+(int)sum;/ t- [# e8 ^- X, A/ O" w" w7 j4 n
- jtsolution.setText(sss);/ |5 V. y4 V. }- q! X
- return ;
6 h! d" N: z/ Y2 q- y - }
4 w7 s) x, R W+ g" l - //m=0,1,2 n=0,1表示六种括号放置可能,并按照这六种可能输出相应的格式的计算式
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- }5 @4 ]# g) g) u! l
- }3 o$ ^8 z$ \8 e9 N+ ^, L
- }
% a3 i* r% T- Z b N9 i/ e/ F - }
: w1 A+ {. {* Y# u - }$ G6 Z6 Q9 ?; r* x& X- [
- }' S7 z. \9 u: I/ J! @: `1 L( }
- if(judge==false)
9 a+ C& N6 J+ ^8 A - jtsolution.setText("No solution!");
3 L# C6 ?3 t) U% h0 {1 B5 A! y' ? - //如果没有找到结果,符号位为06 x2 }; a" H, G0 Q3 t% Y$ k
- }
4 M- c5 I5 Y! ?9 F' F -
2 V: u5 H# v: K - 3 c3 Z: F5 b. F4 d; ~2 y/ M
- public static int evaluateExpression(String expression)/ o# {+ R# h5 b6 x! [7 |: z
- {
) X8 b. Y) G, W0 G/ A1 w; r# W - // Create operandStack to store operands1 I! p( i5 ?& b" U
- java.util.Stack operandStack = new java.util.Stack();
- C7 e `0 D- b" j - $ Q9 r5 v8 h: ]/ n
- // Create operatorStack to store operators! |. ^7 ]. {) `( `' m8 K$ O
- java.util.Stack operatorStack = new java.util.Stack();
. o. Y7 r8 V! R$ ^ -
4 ]/ W3 r" l3 V; g* I, P1 ` `3 g - // Extract operands and operators* r9 L' \ v: `: w0 c
- java.util.StringTokenizer tokens = new java.util.StringTokenizer(expression, "()+-/*", true);
% i" a+ ^3 @2 v# V- L- h0 f3 R6 _ - ( I9 z5 g1 X0 |- s
- // Phase 1: Scan tokens: m' o: L0 k/ @* \
- while (tokens.hasMoreTokens())
9 Y# q/ _; R5 M* _: K8 Y! E - {
' A8 l) e/ l0 U) B - String token = tokens.nextToken().trim(); // Extract a token
9 i2 \' h" K6 _/ ~( I" v - if (token.length() == 0) // Blank space
8 Q3 C5 z1 W+ u; L4 @% e - continue; // Back to the while loop to extract the next token2 H6 a* S- ]. Y; s; [- X M
- else if (token.charAt(0) == '+' || token.charAt(0) == '-')
; @8 {$ A3 B; O: T1 N! S' j1 b - {, ^/ h8 J9 I* }+ l
- // Process all +, -, *, / in the top of the operator stack) B( g" |- T: T
- while (!operatorStack.isEmpty() &&(operatorStack.peek().equals('+') ||operatorStack.peek().equals('-') || operatorStack.peek().equals('*') ||
8 `) p( j5 X. i1 T& k3 a# s1 N - operatorStack.peek().equals('/')))
$ c3 J t5 E8 K+ P - {
! M0 {" w2 j$ o5 K2 g - processAnOperator(operandStack, operatorStack);. l( n* m; q8 L- B0 [- {* F7 N
- }! y( W( K% |, e2 O) x3 m, j; y
- // Push the + or - operator into the operator stack
8 p" w! Z0 ]4 ? - operatorStack.push(new Character(token.charAt(0)));
/ N0 T2 a$ T( _) }* Q& M - }
; L6 L+ M$ b! b I" f - else if (token.charAt(0) == '*' || token.charAt(0) == '/')
6 H! s2 Z |2 W5 O3 R - {( j5 }% s, c, z2 r9 S: Z) ?4 B! b0 M
- // Process all *, / in the top of the operator stack5 ?+ t( Q' ?/ [% L. l& o! s! |# i2 z
- while (!operatorStack.isEmpty() && (operatorStack.peek().equals('*') || operatorStack.peek().equals('/')))
5 v+ b7 s! p9 ]5 p - {2 w3 W& ~+ O& c a; T3 F
- processAnOperator(operandStack, operatorStack);4 u9 Z5 Z5 T- f* [' [
- }* K. P. Y6 I; p( r; g/ e/ `% w7 E, p
-
8 G1 @ Y% o/ p4 {- n - // Push the * or / operator into the operator stack
* F2 s5 s& _0 P! A% d( M - operatorStack.push(new Character(token.charAt(0)));
5 p- \6 y) b F, p0 g - }
" S- k1 [, @6 k1 q - else if (token.trim().charAt(0) == '('); |) x1 f9 A1 v9 A
- {# \* V; u; z. T% X6 _7 F
- operatorStack.push(new Character('(')); // Push '(' to stack
$ p @" L3 s# c4 q. {2 n) w6 L - } J9 ~0 i: G6 S* @* ]4 w2 B
- else if (token.trim().charAt(0) == ')')
1 ~% F+ J& O) {* T9 S- z - {
* J7 h+ v7 O2 T' [ - // Process all the operators in the stack until seeing '('- v4 ^; @, R1 j% _) [4 ^
- while (!operatorStack.peek().equals('('))% m" t) q" ^( f3 T' g, F i: x
- {
A/ j3 B& q% y6 u - processAnOperator(operandStack, operatorStack);/ Q T {, k* k( s" o- q% @6 s9 a
- }& b% v% `/ D* P8 u, Z# g
- operatorStack.pop(); // Pop the '(' symbol from the stack% Q8 g8 E, n% \ i- }* O
- }
* P1 o4 t4 H/ U* t* s# F e, r3 F0 U - else
Y3 p5 ?7 T) z% S- R2 r - {6 H- W1 U! ^0 c( _, _
- // An operand scanned
+ T+ ?% a$ |. f/ U - // Push an operand to the stack
- t0 i/ _% ?3 N$ g# e - operandStack.push(new Integer(token));
3 J2 I% H6 C" l" N3 f+ K - }
( T/ s! E5 r/ X) T - }: a' r+ e9 d4 b$ T/ t( [
- 2 Q8 U- ]) c: n) c5 `# V
- // Phase 2: process all the remaining operators in the stack
+ q8 v% I; z' ~% G/ L9 E- g& ~ - while (!operatorStack.isEmpty())
- r( ~3 F* a6 }# z- c" R1 o - {" P& x" L6 p/ V8 T
- processAnOperator(operandStack, operatorStack);
d* o1 w3 K+ k- G - }
0 E& Z- O0 \7 k& v) R - ) k D! p, g& v5 s
- // Return the result
8 J: @. h' k- I) [ - return ((Integer)(operandStack.pop())).intValue();
0 B% N; f5 P; `' K5 \0 Y+ `- j - }
0 |. q0 w9 l7 A7 a -
" }; s1 _% D. p- y: g5 R5 C - public static void processAnOperator(java.util.Stack operandStack,java.util.Stack operatorStack)+ ^- w% q# U, H. E' Z1 y' p# k
- {' {. k" {( C8 j* O0 `5 g, C
- if (operatorStack.peek().equals('+'))
( L7 j( k1 m/ U0 P+ f - {) J4 \' f- w7 d# c `
- operatorStack.pop();
# ?9 X& ~2 q& a" I - int op1 = ((Integer)(operandStack.pop())).intValue();$ }; O" F3 N( W9 \! i* p, s
- int op2 = ((Integer)(operandStack.pop())).intValue();
. ?3 L3 h% b% B( z0 C, _ - operandStack.push(new Integer(op2 + op1));5 B% C: b; `; B0 z$ y5 C$ V
- }
* Y, L3 L7 U1 d3 Q: S+ D) p4 y* | - else if (operatorStack.peek().equals('-'))
; m, ^' U, [5 I% E$ ^ - {( V) _+ d$ y6 F. q/ u& ~6 ^! B
- operatorStack.pop();
- S8 ?$ O$ o( Q0 T - int op1 = ((Integer)(operandStack.pop())).intValue();' J8 q5 O9 k* H7 j; Y) f
- int op2 = ((Integer)(operandStack.pop())).intValue();7 L6 F& o9 G* Z! F0 O. x4 j
- operandStack.push(new Integer(op2 - op1));8 {% q9 M6 h- |+ z* c' P. t
- }
. `' x1 n; N; z5 u0 l) z% p - else if (operatorStack.peek().equals('*'))2 e: x# g: I& m" @
- {
9 U0 ?1 @ q. Q - operatorStack.pop();
/ E9 ^( Q+ n7 E1 @& X7 R - int op1 = ((Integer)(operandStack.pop())).intValue();
: V6 ?' {) X0 d3 S" P- q - int op2 = ((Integer)(operandStack.pop())).intValue();; X Q' Z) S. |5 _+ w
- operandStack.push(new Integer(op2 * op1));
+ z5 i6 z" }+ c4 G - }
* _# F1 G& _" x @; H, _' I$ Z - else if (operatorStack.peek().equals('/'))" l- x4 c: T& M. a$ H. a. M6 A. I
- {
9 j$ T6 \9 m5 y# s2 _/ R - operatorStack.pop();0 G- e1 I( m1 S. n! V" [
- int op1 = ((Integer)(operandStack.pop())).intValue();8 r1 g( o' C& L% K. T1 o, D0 M
- int op2 = ((Integer)(operandStack.pop())).intValue();- f/ ?. s0 I" L2 U4 I
- operandStack.push(new Integer(op2 / op1));6 E! S" N1 t1 E- `3 |3 I( F
- }% W6 U! ^" R3 g& O/ k' G
- }
, y- y" J' o+ S - & n* i. }8 ^$ T! S% w
- class ImagePanel extends JPanel
+ c: b y& L1 B - {
) o- z) x6 I3 i- d2 O - public void sshow()2 n8 S6 |4 i0 V! l/ B, z, D
- {/ J/ { }; g% Z0 q4 g( z4 x; |4 F
- int i;7 b; G% x$ K6 H
- for(i = 0;i < 4;i++)3 ~" {4 \: b% \; F# Y
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- card[i] = (int)(1 + Math.random() * 52);
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- repaint();
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- protected void paintComponent(Graphics g)
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: H! j6 n, b. F - super.paintComponent(g);
6 X: Q5 Q/ x% o - int i;: R( P* J$ I2 S% l5 ^' \3 v/ S
- int w = getWidth() / 4;
& b! R9 N; F' o - int h = getHeight();$ U' E) @) b/ M( }7 i
- int x = 0;
: Q7 k4 d {! Q0 ^ - int y = 0;
6 {1 |0 E" W0 X# p& J - for(i = 0;i < 4;i++)1 l0 o0 G1 Q, v4 v( V
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- ImageIcon imageIcon = new ImageIcon("image/card/" + card[i] + ".png");: H5 i3 W: z$ w
- Image image = imageIcon.getImage();+ U1 D6 k! o \$ P/ |! d3 n
- if(image != null)1 {# n" W4 d" C0 d
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- g.drawImage(image,x,y,w,h,this);/ ^( ?: p% Z9 S6 w
- }
6 N/ y, g' a g( ~ - x += w;# Q% I3 W1 i0 N8 |* k0 y
- }
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- }
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$ \5 l; {6 b I7 K - public static void main(String[] args)- r: _$ q( V% e* Z* R6 r2 B
- {
4 g5 s) ^2 R, E - TwentyFourPoke_Game frame = new TwentyFourPoke_Game();3 s" f9 w, s2 V7 v h
- frame.setTitle("24 Poke Game");
- z! z6 O( c3 o9 f - frame.setLocationRelativeTo(null);& u" r2 c4 z1 J5 n7 k* X
- frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
* n' ]; H8 T- b" ^ - frame.setSize(368,200);
5 j9 ]8 O& k! J% n& e$ P" Q - frame.setVisible(true);
* l1 h2 \/ T0 ~; T - }
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