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给出四个数字,要求,在其间添加运算符和括号,使得计算结果等于24。
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括号的放置即为决定哪几个数先进行计算。所以,我们先确定首先进行计算的两个相邻的数,计算完成后,就相当于剩下三个数字,仍需要在它们之间添加符号;然后再决定在这三个数中哪两个相邻的数先计算。由此,我们就成功解决了数字的运算次序问题,此时不需要再考虑不同运算符号的优先级问题,因为括号的优先级高于加减乘除。
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# o% x5 V" |5 U( d. d通过循环,我们可以得到第一第二第三次计算的运算符,再通过计算,就可以得出和,若和等于24,即为所求解。/ o- D8 @2 e; H( k" k9 N
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在输出格式中,由于括号的放置共六种情况,故根据计算先后顺序的不同,输出时在不同地方放置括号;
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以下是java源码:, e3 q, v9 Z4 x( a7 M$ ~( i5 P
- import java.awt.*;
$ c& I0 m, j3 ^- x- x - import javax.swing.*;& o0 G7 b$ H" F1 _, p8 @: s
- import java.awt.event.*;
2 p% `3 y& |! p( Y - import java.util.*;0 k! `2 h' u" i- {
- import javax.swing.JOptionPane;
% ]6 B3 z3 ~* V -
9 s' w3 b2 A9 o% j, U" c - public class TwentyFourPoke_Game extends JFrame
5 H9 M/ k# `' D9 u2 f. _: E$ j8 Z - {9 X7 B4 c" c/ W, b& K
- private JButton jbsolution = new JButton("Find a Solution");7 N* L4 m- p3 Q; t$ q$ j
- private JButton jbrefresh = new JButton("Refresh");. A0 i" P0 R2 v( m Z, ^! \" F3 ?9 H
- private JButton jbverify = new JButton("Verify");
4 B5 t& V6 {0 V4 S; n) n1 U3 {9 c - 6 V" x. h' m1 w/ p
- private JLabel jlmessage = new JLabel("Enter an expression:");
! p0 W3 m$ B1 W -
" L$ t+ w+ Y$ @. t# j - private JTextField jtsolution = new JTextField();6 R: g5 Z. x& l0 m& d7 e
- private JTextField jtexpression = new JTextField();/ N4 u( E9 r/ l: I* v) I
-
- S0 k4 T' h- m% X' K - private ImagePanel pp = new ImagePanel();0 P) e8 k9 U+ _
-
8 ~* m( P) q) X4 R: g - private int[] card = new int[4];" Z% s" p5 A7 {) z
- private double[] bcard = new double[4];! }9 }1 Z1 I% c9 x, E2 _% \+ R) n
-
% ?4 d7 E3 d1 w; e/ \ T. y w - private double sum;! O: r/ D. q o% N! i( s) S
- private double[] temp1 = new double[3];
2 u1 U2 v& k- l% S0 B# q - private double[] temp2 = new double[2];
2 Y9 A1 j- B, F o0 }. q# K8 ^0 B, | - private char[] sign = {'+','-','*','/'};
; z! g9 D/ x' |% G - : q* l1 G% {7 F
-
! e" [ U7 u( J8 b( H - public TwentyFourPoke_Game()$ h- P4 i" R; ^& g% d. r3 `. c
- {
9 I, D# F; n4 D - JPanel p1 = new JPanel(new GridLayout(1,3));$ C. g4 O+ y2 n5 G: A2 _
- p1.add(jbsolution);
( g- k! u4 a& H; Y! ?+ C, i7 V - p1.add(jtsolution);$ J" Z; n2 `% b2 N B" k
- p1.add(jbrefresh);$ g- E3 s: s* I4 p+ _5 n
- JPanel p3 = new JPanel(new GridLayout(1,3));& B& w4 n3 p& S4 E( ?
- p3.add(jlmessage);
E7 r8 }! ~- P5 o1 Z# V7 W3 Y - p3.add(jtexpression);
4 q- G) s+ M% W5 }- ~* o; X! | - p3.add(jbverify);
. U) b9 M$ h6 ^1 } H - , P: S! o( V! f
- add(p1,BorderLayout.NORTH);
0 b2 V; j* w; N, }, r( c; K$ g- F - add(pp,BorderLayout.CENTER);
0 E! P6 q: _' U$ U5 D& U: d5 v - add(p3,BorderLayout.SOUTH);3 l3 }% M& i. N% m% ^
- 7 L$ X# u, W- f3 ?% k3 C: X$ I& @, [
- ButtonListener listener = new ButtonListener();
$ o/ F& v9 s- J( y1 M } - jbsolution.addActionListener(listener);" Y; P# e2 D& e$ V4 x+ R
- jbrefresh.addActionListener(listener);( K' C$ F2 l% m9 B* S
- jbverify.addActionListener(listener);9 z- V3 f. A/ T' h/ ^: M. w1 @4 H
- }
]0 n, U' h' H1 k7 i - / F( k6 p; M, v* @
- class ButtonListener implements ActionListener
% n6 l+ V, Y. Y% L' m: J7 M - {
8 e. K9 w6 Z+ ?- w* [ - public void actionPerformed(ActionEvent e)5 T# j( Q0 G: c7 X5 s$ [
- {
, L- J: X: a6 N - if(e.getSource() == jbsolution)! M* F9 A% v. p6 V, ]0 Y
- {$ h. ^& M" K9 G
- for(int i = 0;i < 4;i++)! L6 N& y5 v% I" J% G. M4 R9 A
- {
! Y/ p0 g- `' x% V8 X) b - bcard[i] = (double)card[i] % 13;/ A, L- @1 {9 J% t
- if(card[i] % 13 == 0)
) C$ V! M# g, n+ I# a5 w - bcard[i] = 13;
7 N. M% o+ o6 E - }$ \6 D. ?5 L# r
- search();7 s$ x' a: I* {: l8 f4 O9 F
- }" w! e0 F9 M8 N; m, E/ ^2 o
- else if(e.getSource() == jbrefresh)+ _. p& B w! T8 ?
- {4 ^2 ]7 w& \* i0 Y
- pp.sshow();* Y! T7 L- ^; R9 y5 r9 D+ z( v
-
( b& v5 N4 w2 j. B - }
; b: D8 U8 G. q, V - else if(e.getSource() == jbverify). Y5 J+ |& ~9 y! p- R
- {
- F5 t$ d( y! R0 ]2 ^8 L0 u - String expression = jtexpression.getText();( z2 f! q! [1 R X1 } ]
- int result = evaluateExpression(expression);$ ]% ^' O: X2 A# I9 D$ X- W
- if(result == 24)
1 ~1 z+ @: H V - {
u! K5 L& ?8 |1 p, X. i - JOptionPane.showMessageDialog(null,"恭喜你!你答对了!","消息框",JOptionPane.INFORMATION_MESSAGE);
8 s9 b* Z r) t - }
0 l. i% w( J! L- r8 x - else
8 W# C2 S$ O- ?5 M- g! z - {
/ d* J' ]8 e9 d @$ j- r - JOptionPane.showMessageDialog(null,"抱歉!请再次尝试。","消息框",JOptionPane.INFORMATION_MESSAGE);8 j9 X7 T! x* P
- }% l h* W }; M9 S4 e" d; Q) ]
- }$ g, O4 V$ ]5 Y8 ^) L
- }8 `4 i* w7 ] J7 {
- }
: _1 _; e1 |9 P3 g -
- U3 ^; s8 B# R8 z - public static double calcute(double a,double b,char c)
. F4 g# o8 Q P& i& `) i. E6 o - {
6 C+ ~+ a4 ?: F1 o8 o6 \ - if(c == '+')2 ~! J& @0 j7 t. _
- return a+b;
. Q9 x3 D. ~+ o+ [ - else if(c == '-')
. P! V6 j( e3 t9 D; P - return a-b;
( ^% X. G% A8 J - else if(c == '*')- E/ j$ f: y# Y) {
- return a*b;' E% H! j! ?- Y3 d+ `; i+ h
- else if(c == '/' && b != 0)
& V9 G2 S5 _7 o4 A* ? - return a/b;
, ^/ l9 b; h l/ G8 {' O: x - else
4 a. M* ?* @9 J - return -1;
( G8 a/ ] ^" [9 `) A$ I - }5 F, j9 T$ \$ U1 L
-
( `; O/ f. E0 Y+ N, e0 `* Z - public void search()1 ^. p: L! r: U1 ^& |
- {
) k# M; K9 Q6 K6 i j8 m/ r - boolean judge = false;9 m4 v7 J1 b$ ]" G4 ?: J! N
- for(int i=0;i<4;i++)( g Y) \0 O1 _$ u( G/ I! K
- //第一次放置的符号
% H6 O. d$ H* g9 H# x0 P - {* t" m$ S7 D: _! R
- for(int j=0;j<4;j++)" a* g: o+ D2 |) g% Z7 {* L
- //第二次放置的符号. l+ h! |6 L) ?4 Z' R
- {
& b- M: d4 E& k3 b% E: W1 j - for(int k=0;k<4;k++)# C5 B/ {% }8 g7 T! ]$ B' z; ]9 @
- //第三次放置的符号) i: R" G0 L7 N
- {
5 }$ i: A/ r |. w! Z- g! R - for(int m=0;m<3;m++)9 p8 g7 [& H( B4 W$ @+ M
- //首先计算的两个相邻数字,共有3种情况,相当于括号的作用6 j1 t& s! Z* e! |* u/ {
- {5 Q6 H& I4 @$ w# e, y
- if(bcard[m+1]==0 && sign[i]=='/') break;3 f* e6 D+ w, M- c6 I1 x
- temp1[m]=calcute(bcard[m],bcard[m+1],sign[i]);
- h6 I, o5 ~: P/ D) S! d$ Y/ @ - temp1[(m+1)%3]=bcard[(m+2)%4];
; t0 g+ W) q8 i$ Q, R - temp1[(m+2)%3]=bcard[(m+3)%4];" r2 O6 i% Y1 s+ d( Y' q# c+ x
- //先确定首先计算的两个数字,计算完成相当于剩下三个数,按顺序储存在temp数组中
" O4 L1 V& F/ F - for(int n=0;n<2;n++): r- C9 d% B9 N( [7 |7 h
- //三个数字选出先计算的两个相邻数字,两种情况,相当于第二个括号
$ }" j/ Y7 S0 J7 J0 h1 O0 G# h - {
. g- b5 n: {2 @0 x5 D O' v0 ]6 g - if(temp1[n+1]==0 && sign[j]=='/') break;! i& f" c1 \1 }6 P( D, E; m
- temp2[n]=calcute(temp1[n],temp1[n+1],sign[j]);( F7 \1 }1 {' _* G9 m
- temp2[(n+1)%2]=temp1[(n+2)%3];8 X# P! ]+ a7 w, j" S" i" G$ C; I) J
- //先确定首先计算的两个数字,计算完成相当于剩下两个数,按顺序储存在temp数组中
7 D" u5 F6 {$ Q0 n8 X - if(temp2[1]==0 && sign[k]=='/') break;& s7 V: b p6 V7 \: o! c% {% Z
- sum=calcute(temp2[0],temp2[1],sign[k]); a* a ?) [5 ? O1 j! K( `4 e8 W
- //计算和
+ g" r: g' F+ @5 [ - if(sum==24)
' K9 x* n9 [. ^8 d) Z, b% N& e7 J - //若和为24$ w6 U/ R1 Z0 a' |! |
- {
: s& r# H0 l/ ^! r- Z6 ]( S3 x - judge=true;' P9 h4 _: C! o! \: e. a6 I
- //判断符为1,表示已求得解. X n. Y6 _/ g: j/ b
- if(m==0 && n==0)
/ ~5 [; [* _; c - {+ v. G- l9 b& R' w5 z5 A, k
- String sss ="(("+(int)bcard[0]+sign[i]+(int)bcard[1]+")"+sign[j]+(int)bcard[2]+")"+sign[k]+(int)bcard[3]+"="+(int)sum;
' ~7 h1 E8 ]* U - jtsolution.setText(sss);3 S' D$ M7 v6 N1 D
- return ;' `. Q- m$ m9 T4 b4 z% T$ H/ q
- }
1 B& Z0 t3 z+ _: ^/ D) _ - else if(m==0 && n==1)
% H \; D% P% Y" S$ y E - {( c* n) Y5 d5 p0 C/ ]2 u
- String sss ="("+(int)bcard[0]+sign[i]+(int)bcard[1]+")"+sign[k]+"("+(int)bcard[2]+sign[j]+(int)bcard[3]+")="+(int)sum;
6 Y/ m+ \+ c% Y- H/ U7 Z9 \- G - jtsolution.setText(sss);' G4 |/ `2 S4 a: P7 [% W
- return ;
. A& i; w5 P6 I3 G - }
: m- y8 A, ]& ]. B2 t - else if(m==1 && n==0)
- f/ R+ t" Y. f$ v6 N* Z7 L - {; k9 ?0 U% w8 ]2 K
- String sss ="("+(int)bcard[0]+sign[j]+"("+(int)bcard[1]+sign[i]+(int)bcard[2]+"))"+sign[k]+(int)bcard[3]+"="+(int)sum;' Y/ e; ~4 v# V" S& J
- jtsolution.setText(sss);* O& [9 A( b5 X' G5 W* q( J0 D3 j- w
- return ;( h5 [$ L7 |4 r- H8 P8 L
- }
1 g: @+ s* T* g! s - else if(m==2 && n==0)$ |5 K" b n, x6 E. N' s* b7 H
- {0 [4 [+ f/ i# H- O. r* j
- String sss ="("+(int)bcard[0]+sign[j]+(int)bcard[1]+")"+sign[k]+"("+(int)bcard[2]+sign[i]+(int)bcard[3]+")="+(int)sum;3 l) U+ q* w" m2 B; I, y
- jtsolution.setText(sss);3 c6 |1 x1 J' D- S; x, Z
- return ;# X& ~( k5 C) i4 x! } A& Z8 R/ N* k
- }
; ]0 C; \- S7 b A7 F" f - else if(m==2 && n==0)
4 S+ r1 I; k O# s5 m! K - {
* O9 ]; T1 M/ i - String sss =(int)bcard[0]+sign[k]+"("+(int)bcard[1]+sign[j]+"("+(int)bcard[2]+sign[i]+(int)bcard[3]+"))="+(int)sum;* o9 |$ Q4 p/ N9 j/ n6 q. Q1 A
- jtsolution.setText(sss);
1 M& g6 `& K/ G, I3 I0 L - return ;" ?4 b6 Q' e+ N
- }
( g0 j' E9 ^5 ~1 T9 g0 q - //m=0,1,2 n=0,1表示六种括号放置可能,并按照这六种可能输出相应的格式的计算式
7 ^ c( w q: O& @% v# ~ - & J O8 t' H( r" g+ t/ {, j
- }
' o2 x7 Y- U( Y - }
5 q* s8 r' E0 L' l* j9 k8 v' { - }
4 R) S! [6 L9 M; E$ a - }
5 K1 N+ U. `, T0 O% v( X - }
, ]! `* w$ P, H0 k6 L S, u - }
- a0 e% p" V8 e q7 i - if(judge==false)1 I9 Y6 v: Q; y
- jtsolution.setText("No solution!");
6 ]! x; L) P( i0 W - //如果没有找到结果,符号位为0. N4 |7 H! @# c: f
- }
i5 L( w/ s, u* G; l( T - 7 ]- k. E& U: |" M
-
* O+ Y6 ?1 S. O% d Q - public static int evaluateExpression(String expression) J# Q; g- n4 q, _# T; Y, @
- {6 D1 R$ j% |" W2 C9 y
- // Create operandStack to store operands7 c, Q' K3 @0 K2 I: C4 ?" S
- java.util.Stack operandStack = new java.util.Stack();
! Z: n* a: K# I - / N. h9 {/ H; o# m+ R
- // Create operatorStack to store operators
# Q1 ?" L |! n5 M0 _) [9 ~3 p - java.util.Stack operatorStack = new java.util.Stack();. R! D/ t$ V1 Q, \ C
- 4 C* ~& _0 O: W3 u6 I
- // Extract operands and operators/ T0 r& X; r% y- C
- java.util.StringTokenizer tokens = new java.util.StringTokenizer(expression, "()+-/*", true);
8 G+ R( j4 p" \( ? - ! `; g" z3 Y1 U9 i! I8 q) `
- // Phase 1: Scan tokens1 g4 V& ?4 o" m' \) x5 p. `
- while (tokens.hasMoreTokens()), E+ `3 m# a9 v/ x% D2 A
- {
- N+ l/ R- E5 B3 ] - String token = tokens.nextToken().trim(); // Extract a token
$ k8 |; [7 F: x- o f* w - if (token.length() == 0) // Blank space- P' z, b. E8 r9 A/ T4 r4 ?, T
- continue; // Back to the while loop to extract the next token
Q7 [, b. y3 @3 X - else if (token.charAt(0) == '+' || token.charAt(0) == '-')
$ \' M1 d' S1 w; K E - {
3 p* L2 p6 a9 T; F% E1 o% h9 p- F - // Process all +, -, *, / in the top of the operator stack
* p5 H7 Y6 Y0 `/ s0 h! t/ C m. K: _ - while (!operatorStack.isEmpty() &&(operatorStack.peek().equals('+') ||operatorStack.peek().equals('-') || operatorStack.peek().equals('*') ||
- \/ F* j/ {* d" a# ~ - operatorStack.peek().equals('/')))
- P% [4 L. W) y# V1 @: _$ K* q - {
" H, O- P8 f) g, P - processAnOperator(operandStack, operatorStack);
4 D. U! G3 B9 J6 t# _8 D - }, g4 `, G5 F" |* O- ^" r
- // Push the + or - operator into the operator stack
+ L! R1 x6 ?# ~7 ~ - operatorStack.push(new Character(token.charAt(0)));% z" Y- i; N+ X% Z- k: J& R- Z
- }6 T. l* O& N3 ^' ?: \5 B# V; _
- else if (token.charAt(0) == '*' || token.charAt(0) == '/')
# A7 K& o% O& `5 |% P - {
0 A4 s1 k% [" s5 t1 N - // Process all *, / in the top of the operator stack! K3 T, F, x/ E6 Y! R
- while (!operatorStack.isEmpty() && (operatorStack.peek().equals('*') || operatorStack.peek().equals('/')))& d# g9 Q8 W7 [4 s6 A
- {
; l( X. @+ h7 K - processAnOperator(operandStack, operatorStack);
5 p9 {$ J/ c; e5 y# }( g0 \7 a - }2 I8 u9 d1 v4 j+ B4 _& r- X
-
6 {" j! s9 I' F9 y( t. n - // Push the * or / operator into the operator stack
, n; n# k( E6 Z: I" X, [& X - operatorStack.push(new Character(token.charAt(0)));
1 p; w. P6 W/ z- _" j* C+ b6 K/ V - }7 D' l' w- X; }$ a6 G; ]( o
- else if (token.trim().charAt(0) == '(')
3 }7 ? B! D% L. [ - {
. o: q a u3 d3 l - operatorStack.push(new Character('(')); // Push '(' to stack- ?; Z+ m5 B Y$ f1 e6 }! D
- }
3 U. D/ q8 @0 w! m - else if (token.trim().charAt(0) == ')')
6 T' ?# ?. [8 @8 I! T4 i - {& x% A3 j; S2 |9 i
- // Process all the operators in the stack until seeing '('1 b$ m" I" s5 a
- while (!operatorStack.peek().equals('('))6 Y1 t1 _9 v: @4 J1 b: D
- {* K; \- _$ n* ^
- processAnOperator(operandStack, operatorStack);
6 ~% D, ~) ^* ]$ P) C! d' T3 g - }( X: w- `; H; {! X( P+ |. ]- u8 v
- operatorStack.pop(); // Pop the '(' symbol from the stack
4 k4 X* I* T \; j, q( P' F - } ^0 f7 Y4 g3 C5 m2 t
- else
& u/ o. \5 r. y - {( ~* ~2 ?) Y* q
- // An operand scanned' T, L9 X5 ?) [4 G+ p! z: Z: i
- // Push an operand to the stack
/ W E4 T+ S5 y; m; v - operandStack.push(new Integer(token));5 E0 u& u8 |) k- v% S% |+ \
- }
" T3 P; s1 a0 g6 { - }
1 D. T) j0 t$ {3 j9 V2 i -
' f- z; f) m) M" u - // Phase 2: process all the remaining operators in the stack- K; K3 p, x, f6 X( U
- while (!operatorStack.isEmpty())4 V! C9 Q! F" F7 u5 H" b; K
- {4 |$ A9 L0 @% I1 w) B" i
- processAnOperator(operandStack, operatorStack);
: ]9 J' h6 b& C - }
+ U4 x, x _. ~$ K. }9 M" D6 a - 2 J, x* K2 J! T- e" d0 ?% J3 w+ ?
- // Return the result
4 ]) M# t6 ?. Q, v( m) y - return ((Integer)(operandStack.pop())).intValue();( V+ k7 o' r0 R
- }
7 L5 S. v8 O! v( ], r - 5 K. z2 ^& \: J! Y3 z+ r
- public static void processAnOperator(java.util.Stack operandStack,java.util.Stack operatorStack)
- Z" ~; x7 I! e8 Q X - {
4 ]; C8 i) y3 x8 A' @. l - if (operatorStack.peek().equals('+'))
, [+ z; L# {! c - {( N* l2 {5 K i
- operatorStack.pop();
3 K0 z2 Z7 G( c4 f - int op1 = ((Integer)(operandStack.pop())).intValue();: W: W' O% ?" o/ j$ B
- int op2 = ((Integer)(operandStack.pop())).intValue();4 P! `0 e7 m; I; H; T: Z2 R* h! P
- operandStack.push(new Integer(op2 + op1));
7 i$ a0 K1 Q4 W) P5 `. z - }
) r3 j$ M7 W: c- A - else if (operatorStack.peek().equals('-'))% K. P- o+ u; ]$ e
- {
. E3 q! }$ a+ | D, [ - operatorStack.pop();
- R2 ]7 J9 ]6 B3 M+ P* } - int op1 = ((Integer)(operandStack.pop())).intValue();; b/ k! I( L u. ~8 o8 w8 r
- int op2 = ((Integer)(operandStack.pop())).intValue();
5 \1 h- g/ ]0 ]) D9 U! o - operandStack.push(new Integer(op2 - op1));
" D; j! F. D. D+ ]: T* n - }, }" F: F6 i: l# |
- else if (operatorStack.peek().equals('*'))7 P: u; H2 p2 k6 U5 p. J
- {
! x, g! r$ m% Z2 ?0 w - operatorStack.pop();, s" t( }2 @, w; N8 X; `
- int op1 = ((Integer)(operandStack.pop())).intValue();3 c3 ~% r& H4 d+ E+ x5 C: s
- int op2 = ((Integer)(operandStack.pop())).intValue();/ [! ~$ w& _: n3 I! |' o. j% p
- operandStack.push(new Integer(op2 * op1));
$ y1 Z9 R: z- }$ T/ Z8 h - }+ k* e5 Z) M+ P! {
- else if (operatorStack.peek().equals('/'))
0 ]: ]/ a5 j4 ~* z" L - {
+ C& q2 q/ F* G+ H. ^" u - operatorStack.pop();
0 }( P7 ^* A9 I$ H - int op1 = ((Integer)(operandStack.pop())).intValue();
3 [4 {4 R9 ]: D1 D) F- D6 v3 H - int op2 = ((Integer)(operandStack.pop())).intValue();
6 M; V% M8 K0 g! `( B3 r* c! V; }7 W( r' { - operandStack.push(new Integer(op2 / op1));. R; F- \- M/ C% s8 o. b
- }
3 y+ l' L0 x) E# f: I - }; e7 D6 k9 _( E" r" f+ G7 n
-
# N$ N3 d- j4 N5 k) W* g- w F& ^ - class ImagePanel extends JPanel/ ~/ R$ |/ L6 m+ k* f
- {' b1 u7 b! M3 k, r
- public void sshow()& ~/ v( C; C( m3 S, e- v4 X
- {
) M$ ^- j* R& [# j3 T - int i;* z2 x m0 a; F9 h; \+ @0 X8 Q, i5 D
- for(i = 0;i < 4;i++)
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- card[i] = (int)(1 + Math.random() * 52);
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- repaint();
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- protected void paintComponent(Graphics g)
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6 Q; |2 ], d; ]$ [* H2 d7 P! c - super.paintComponent(g);
+ H2 t+ c; q+ \) c" r* U. ? - int i;
F& G7 O Z9 A: @5 E% \8 G& D# ]0 l - int w = getWidth() / 4;
: V1 F2 w, t) E' A! b& V - int h = getHeight();
" V1 b' J* }0 ?* G" }" W - int x = 0;4 G0 C2 V4 a) n$ Y. x0 x
- int y = 0;
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! X" o8 [! S# C# c$ V - ImageIcon imageIcon = new ImageIcon("image/card/" + card[i] + ".png");
; o i, v& M- W0 I5 U, p$ ^ - Image image = imageIcon.getImage();+ z' x! W ]5 [3 M# ^
- if(image != null)$ Z; t* J5 p! R; r+ y
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- g.drawImage(image,x,y,w,h,this);
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- x += w;
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- public static void main(String[] args)6 D5 l. V9 Y! ]3 t$ w' g1 P& `
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- TwentyFourPoke_Game frame = new TwentyFourPoke_Game();
+ T3 r! V7 O( \; F - frame.setTitle("24 Poke Game");3 z; k' p. a- q
- frame.setLocationRelativeTo(null);/ w5 Y/ E$ R; m
- frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);2 F; g4 K0 m& t% x
- frame.setSize(368,200); m+ k" d# H( n) t1 N4 z. K
- frame.setVisible(true);
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- }
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