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给出四个数字,要求,在其间添加运算符和括号,使得计算结果等于24。& b' \" J* M: _+ J: U" @ K3 ~( q/ h3 L
7 v0 N" R5 t8 |# i, E/ c* v& y3 i 括号的放置即为决定哪几个数先进行计算。所以,我们先确定首先进行计算的两个相邻的数,计算完成后,就相当于剩下三个数字,仍需要在它们之间添加符号;然后再决定在这三个数中哪两个相邻的数先计算。由此,我们就成功解决了数字的运算次序问题,此时不需要再考虑不同运算符号的优先级问题,因为括号的优先级高于加减乘除。+ Q! R9 [% ~2 T+ T
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通过循环,我们可以得到第一第二第三次计算的运算符,再通过计算,就可以得出和,若和等于24,即为所求解。" f3 T+ x0 n# m H# @
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在输出格式中,由于括号的放置共六种情况,故根据计算先后顺序的不同,输出时在不同地方放置括号;
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以下是java 源码 : ]5 m. o3 w. i
import java.awt.*;+ l0 `. A7 M: X! s# O/ \: s
import javax.swing.*;
( `3 m( I. b* M3 L! ^7 z" s import java.awt.event.*;$ ]3 m5 ~1 I8 R# Y H) N
import java.util.*;, F+ Q% N1 X1 W8 A% f: R
import javax.swing.JOptionPane;9 y/ |# b& F; a- u. G E
" y/ j: d! J# ~* W. r) _. B4 \ public class TwentyFourPoke_Game extends JFrame
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) x% N6 {1 w1 G private JButton jbsolution = new JButton("Find a Solution");
& s, m0 V2 A9 l8 k8 m private JButton jbrefresh = new JButton("Refresh");
! j3 G2 Y3 N4 h4 Q% m private JButton jbverify = new JButton("Verify");
/ T& J4 s* T! Z' Q4 K2 R$ t2 a& v 8 @* D* o. w! S' e! } ^1 Y
private JLabel jlmessage = new JLabel("Enter an expression:");/ T; t' @+ t* ^7 K, _: `1 {
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private JTextField jtsolution = new JTextField();7 n7 \8 s" G- R5 e
private JTextField jtexpression = new JTextField();
* n' Z, D K! g6 {
2 d+ D0 Z% R# T; ~) ] J private ImagePanel pp = new ImagePanel();1 c/ V4 b0 j6 @- r* \8 L8 n _$ F R
# T0 Q6 P+ D9 |9 X private int[] card = new int[4];3 {7 @+ _7 ~0 B8 x1 ~5 X; _
private double[] bcard = new double[4];
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private double sum;. G" y `7 o2 h# D' l% N; E
private double[] temp1 = new double[3];
. f. T% V2 d3 J6 y* y private double[] temp2 = new double[2];& `- F! F4 i0 |) ?' l
private char[] sign = {'+','-','*','/'};1 K7 Y, }/ W' p2 e8 z
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, R7 P( }" K' n2 j public TwentyFourPoke_Game()8 M5 {2 T7 u% P1 p7 {6 A
{
, Y% C- @5 E% p3 o# H+ _/ { JPanel p1 = new JPanel(new GridLayout(1,3)); m r, W8 Y) `( h3 t
p1.add(jbsolution);
$ e2 h1 d1 E6 w; c# B p1.add(jtsolution);% w+ o. F7 h: `) I
p1.add(jbrefresh);
8 @9 M3 M3 n% n( H JPanel p3 = new JPanel(new GridLayout(1,3));
( W- s" I3 T( h+ R1 V p3.add(jlmessage);+ K5 y/ P' |0 Y4 ?4 K" l
p3.add(jtexpression);
9 `* O Q- U+ _4 v" V p3.add(jbverify);
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add(p1,BorderLayout.NORTH);
3 b. B$ l3 o M- ]! H5 [( P$ I add(pp,BorderLayout.CENTER);
- x h3 i& W5 {( \0 J* O9 v add(p3,BorderLayout.SOUTH);* a q6 m# g+ A
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ButtonListener listener = new ButtonListener();/ L u4 _, V2 e9 S* W
jbsolution.addActionListener(listener);6 }4 G9 T+ e1 D0 ]0 M, y
jbrefresh.addActionListener(listener);
2 j! h7 X; E) j jbverify.addActionListener(listener);) v" N' ?! G; o
}
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& E) {# p. P( V. a$ ]3 q class ButtonListener implements ActionListener
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public void actionPerformed(ActionEvent e)4 ~. ^8 H: |0 g$ @
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if(e.getSource() == jbsolution)
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for(int i = 0;i < 4;i++)' X$ f' _; g6 y8 o
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bcard[i] = (double)card[i] % 13;6 d0 x# R& h M9 g
if(card[i] % 13 == 0): @! g+ H3 N1 f
bcard[i] = 13;
! o, E! D8 v, i7 x }
, V0 K8 ^0 Z d; [) W/ k search();
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else if(e.getSource() == jbrefresh)
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1 A1 G9 J1 G+ M3 w+ ]3 R, R; B pp.sshow();
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6 {8 y3 F5 j% n1 o1 X% c }
3 w" N4 V7 }6 J0 m else if(e.getSource() == jbverify)- ]- N% u+ s; c( X% C+ ?- }
{
5 `$ @ H) f5 r( G* s( |! g7 r# d String expression = jtexpression.getText();
2 t! ^ u& s! o& P7 A int result = evaluateExpression(expression);
! V7 h1 ~" J% ^8 X* ~8 J if(result == 24)
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JOptionPane.showMessageDialog(null,"恭喜你!你答对了!","消息框",JOptionPane.INFORMATION_MESSAGE);* p' L) v2 `# R6 F. v0 Z2 `
}
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{
# q0 w: X3 M, J. T5 m JOptionPane.showMessageDialog(null,"抱歉!请再次尝试。","消息框",JOptionPane.INFORMATION_MESSAGE);
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public static double calcute(double a,double b,char c)
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6 J0 f7 _; [) A' M6 Q4 y if(c == '+')
* t# n s! D. g7 L return a+b;
: }* e6 d! j3 E4 Y else if(c == '-'); ~' r, U. L" k3 u1 O! O
return a-b;
# u C1 Z6 L& O# t7 F, E# ~ else if(c == '*')+ \1 G1 X# Z! V: M
return a*b;1 w, c7 G/ J6 I3 a
else if(c == '/' && b != 0)& H5 G2 g6 | o- H$ q3 i
return a/b;7 D- \) \3 r6 c# x1 ^) S
else% H+ X: _$ }6 F' w1 ]
return -1;% `) k- S) u. U# h
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/ x9 J8 ~1 p3 W! q! I public void search()
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boolean judge = false;
' j7 R6 W( v# d& p' m5 R/ I7 e for(int i=0;i<4;i++)
! f/ r7 t2 K3 W* c% O //第一次放置的符号
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: r* b1 F/ n$ \% j) J for(int j=0;j<4;j++)5 ^+ C: a: o9 J. M/ [
//第二次放置的符号
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- q7 [4 @. c* g8 I9 z. r for(int k=0;k<4;k++)
9 ?5 L+ Q& p6 h! S0 W" y //第三次放置的符号% ~7 w% c3 i/ f9 @4 I
{
" A# T0 {1 ]0 @: @1 C1 b for(int m=0;m<3;m++). M( x: x; M6 T' h y: h. ~
//首先计算的两个相邻数字,共有3种情况,相当于括号的作用3 _( `2 x! L( r* R9 Z% w% w& _
{
4 }& s+ } c* k$ t. N- V2 R0 k if(bcard[m+1]==0 && sign[i]=='/') break;
3 e- R0 O0 C. h3 I8 q P) H7 d temp1[m]=calcute(bcard[m],bcard[m+1],sign[i]);# A- g, q5 z, N4 s& d
temp1[(m+1)%3]=bcard[(m+2)%4];
5 A, {, S/ Z, `4 k1 V/ K- k temp1[(m+2)%3]=bcard[(m+3)%4];
. `5 W( r C; K% X9 j //先确定首先计算的两个数字,计算完成相当于剩下三个数,按顺序储存在temp数组中
2 J- m0 J! I) i6 _$ k) ~: ~" g for(int n=0;n<2;n++)
2 y7 k. t; `, f o //三个数字选出先计算的两个相邻数字,两种情况,相当于第二个括号
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if(temp1[n+1]==0 && sign[j]=='/') break;
5 E+ x; J7 t. D: B) k temp2[n]=calcute(temp1[n],temp1[n+1],sign[j]);5 i" D( ^6 E1 o' `) |- E" |
temp2[(n+1)%2]=temp1[(n+2)%3];
( N, P, Z) Y4 b2 u% { //先确定首先计算的两个数字,计算完成相当于剩下两个数,按顺序储存在temp数组中
! S/ z" n" r+ S- |0 i if(temp2[1]==0 && sign[k]=='/') break;! S; M9 Q$ w: d7 Y' i( e2 l- K
sum=calcute(temp2[0],temp2[1],sign[k]);2 }( {, ]8 u' Q' ?0 n, J
//计算和
) e0 M4 W+ C, E$ Y$ E0 z if(sum==24)
4 n7 O& h T& F% E7 v! C //若和为24
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judge=true;; e o+ ` y) _/ H; m+ L
//判断符为1,表示已求得解5 i! V3 H7 t# d5 _1 ?
if(m==0 && n==0)
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8 _4 F" _1 ?' p: U! p String sss ="(("+(int)bcard[0]+sign[i]+(int)bcard[1]+")"+sign[j]+(int)bcard[2]+")"+sign[k]+(int)bcard[3]+"="+(int)sum;% ^/ h- R5 T& o6 s- w4 c
jtsolution.setText(sss);. ^! P( P6 E, u
return ;
' Y6 r+ J, x& U! G+ u: V5 f. n }
8 r9 J; }+ T6 H9 V( Q# m% d else if(m==0 && n==1)) f4 E6 R/ }5 Q+ l
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String sss ="("+(int)bcard[0]+sign[i]+(int)bcard[1]+")"+sign[k]+"("+(int)bcard[2]+sign[j]+(int)bcard[3]+")="+(int)sum;+ D2 u- m* D5 K* l {
jtsolution.setText(sss);
5 m" `8 {% ~# Y* N return ;
4 {6 l9 ~# M J4 b, H4 A }
- p4 }! S6 Y+ b9 o/ g- O1 t5 v3 i* p else if(m==1 && n==0)0 d ?- e4 F: T! D
{
* I0 T( W; R7 _4 J$ [* D, I8 t( H String sss ="("+(int)bcard[0]+sign[j]+"("+(int)bcard[1]+sign[i]+(int)bcard[2]+"))"+sign[k]+(int)bcard[3]+"="+(int)sum;0 \( A9 C0 i* I
jtsolution.setText(sss);
9 u J- o4 V/ T! u# L# o return ;8 N- ?$ N0 a6 ?. @
}
' r( D, p% I8 @* I* x3 B/ ^/ X. | else if(m==2 && n==0)
+ b, W0 a" i- B: j$ g! E6 b) Y {
& L7 a; {: _1 Y String sss ="("+(int)bcard[0]+sign[j]+(int)bcard[1]+")"+sign[k]+"("+(int)bcard[2]+sign[i]+(int)bcard[3]+")="+(int)sum;. S- E y D" l! A0 m( w$ a# p% x$ X
jtsolution.setText(sss);
. l) s' d( ]; c( q7 m/ ]) x. X' q/ \ return ;" u' \* f6 \ _% a3 s/ @$ v
}
% ^ K M$ P) m* G, D else if(m==2 && n==0)1 J3 ` e/ y/ b9 I7 o
{
4 R' c, l' Y: b+ C5 X- K5 q String sss =(int)bcard[0]+sign[k]+"("+(int)bcard[1]+sign[j]+"("+(int)bcard[2]+sign[i]+(int)bcard[3]+"))="+(int)sum;3 [0 e+ B$ p! g6 y3 W9 D( \* c
jtsolution.setText(sss);; g0 U7 _* P1 m9 w1 n" |( m
return ;2 t2 z5 a: d2 ~2 q9 h3 z) d% g
}
# z1 L; b. L5 E //m=0,1,2 n=0,1表示六种括号放置可能,并按照这六种可能输出相应的格式的计算式
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}
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}
& }5 t% U* Y$ ~ if(judge==false)
6 T! W/ p* D0 k+ L1 b- _& S" R jtsolution.setText("No solution!");7 v. {! ^* p; u8 B3 z
//如果没有找到结果,符号位为0# ]8 p* K! P9 N" P
}
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public static int evaluateExpression(String expression)# O8 x! ^& _' _# l( \
{
3 h* A, s% Q2 ]& ], z // Create operandStack to store operands
f4 \5 ] n0 w2 F java.util.Stack operandStack = new java.util.Stack();
+ C) t4 f/ S$ e1 D+ d! p0 n/ b 8 \* [- ~9 g/ ^0 O, P
// Create operatorStack to store operators
# M9 _. Y+ O! J( ] java.util.Stack operatorStack = new java.util.Stack();
, O+ _- o, ]. B# I8 w# Z9 h( n
# w4 k5 x4 @% ]) m5 j' P- U8 Z% C // Extract operands and operators# d' C0 T" V, {; O4 u
java.util.StringTokenizer tokens = new java.util.StringTokenizer(expression, "()+-/*", true); t5 V9 ~" D# F4 x
8 s/ f. g: K2 Z5 d7 G7 O // Phase 1: Scan tokens9 y x2 k0 K1 T8 D" b4 A( r
while (tokens.hasMoreTokens())) i' D( J1 G) Q2 B3 c) H' p
{
4 G3 j; l2 P% Z: q String token = tokens.nextToken().trim(); // Extract a token
' _5 n9 N! N# E1 b* J0 G. n0 S8 E if (token.length() == 0) // Blank space
% H' N5 k, c' c1 e. m' |; c, o4 M6 N continue; // Back to the while loop to extract the next token
6 |! I8 O: \4 A. K/ C* {, n+ H( z; y7 C else if (token.charAt(0) == '+' || token.charAt(0) == '-')& V+ T% k9 B( |
{
v* |2 f& {: y3 u6 T/ e // Process all +, -, *, / in the top of the operator stack
2 U" {! G: z6 l. ^& ?9 w" p while (!operatorStack.isEmpty() &&(operatorStack.peek().equals('+') ||operatorStack.peek().equals('-') || operatorStack.peek().equals('*') ||& t3 p4 l$ {" I2 ]9 @
operatorStack.peek().equals('/'))) \4 F. t2 f& g
{! o7 J, C3 s1 M. B8 d+ O
processAnOperator(operandStack, operatorStack);
. |6 g+ M2 ~1 Z }
- X! w a3 R# h; j! n // Push the + or - operator into the operator stack
$ W- C5 k3 A0 c% m6 ] operatorStack.push(new Character(token.charAt(0)));* q2 A9 x W: _ q
}
$ j1 @# l' R: Q else if (token.charAt(0) == '*' || token.charAt(0) == '/')9 [+ {. Z5 l) Y; W m% k
{
5 h: b! i, h4 N/ t& e6 ~6 w // Process all *, / in the top of the operator stack
& P, l6 J, { t3 |. o' | while (!operatorStack.isEmpty() && (operatorStack.peek().equals('*') || operatorStack.peek().equals('/')))
$ \4 `( ?/ M4 A1 J8 o. V! X* [ {; O0 k6 H6 ~% G8 r3 r
processAnOperator(operandStack, operatorStack);+ ~1 [; ]$ B+ t2 N" Q# I/ x$ `
}
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// Push the * or / operator into the operator stack
' a/ p3 C; P% g/ {: O/ A: F2 A operatorStack.push(new Character(token.charAt(0)));( |0 `# w( A3 k
}
% H* G" `# w# x; c6 I else if (token.trim().charAt(0) == '(')
6 A/ E; a; a. b; b {. I) X- F* A1 y- k, c6 X6 P" u9 s
operatorStack.push(new Character('(')); // Push '(' to stack9 d* Z1 L- V" u; O
}
( c2 |) c5 y e5 y else if (token.trim().charAt(0) == ')')
3 ^' Y' l3 Z2 V* n1 @' z U {
, H+ ?+ H- ~7 E4 Y+ s // Process all the operators in the stack until seeing '('
: k: Q7 n" M' {5 E3 j' D" x, Z% ` while (!operatorStack.peek().equals('('))
+ z* K( [: S" g {
8 i$ n) R3 G% }' j processAnOperator(operandStack, operatorStack);* N, i/ G( R$ _" O1 `# R
}: {* K& `" p0 ^! Y+ v9 @3 D" }
operatorStack.pop(); // Pop the '(' symbol from the stack
4 O% O9 g, m4 ~' D* w# b* a }
1 K! Z! ^6 z- ^, E else
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// An operand scanned5 `" U3 E# O( z- L t
// Push an operand to the stack
: c" p) c2 S# T" X: ~8 N9 o: ]+ Z operandStack.push(new Integer(token));: ^) l- I% j9 y2 z$ w" s' f6 }, ?' ~
}
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' @7 S) I6 p" a // Phase 2: process all the remaining operators in the stack
0 [( s; I% ^$ n7 R1 Z" w while (!operatorStack.isEmpty())6 j$ D- Q( v( x" O# V
{
$ A3 }/ q8 b; H O& ?$ s processAnOperator(operandStack, operatorStack);3 K5 o; }' O; z
}1 n5 |' n! c0 @% W! a
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// Return the result7 |8 @0 V2 ]* m- h/ _" ]) l3 I! a
return ((Integer)(operandStack.pop())).intValue();3 p( m7 l- j" X$ ~
}
% @/ l* @0 l1 n+ r( n( J1 b& V $ ]% U* X! X8 Q$ V2 z3 k
public static void processAnOperator(java.util.Stack operandStack,java.util.Stack operatorStack)1 h8 A( r+ E& N6 z
{
7 ]; g& a% G& P% |/ ]" E if (operatorStack.peek().equals('+'))
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operatorStack.pop();
& C4 B3 x9 q7 O$ Y/ I int op1 = ((Integer)(operandStack.pop())).intValue();+ V h6 j1 h5 c$ j" c8 f! i7 ]
int op2 = ((Integer)(operandStack.pop())).intValue();# T- n0 t8 u H7 \+ `
operandStack.push(new Integer(op2 + op1));- ?5 d7 c4 a4 C
}
" o8 @4 {) M$ f else if (operatorStack.peek().equals('-')), W; L7 n2 }# M; y
{& B& c0 Z9 o# U5 F& h
operatorStack.pop();
$ W; Q n3 Q+ `. M( j int op1 = ((Integer)(operandStack.pop())).intValue();
" o: i/ F; h+ ^ int op2 = ((Integer)(operandStack.pop())).intValue();
) m' c8 a- R+ y# n+ W3 @ operandStack.push(new Integer(op2 - op1));9 |9 B- J' z6 I3 L6 L& x. E
}, j7 J, Y6 R% E7 y
else if (operatorStack.peek().equals('*'))
/ T [- s: }' m {
) Y6 `" X5 f1 o6 h+ t2 j operatorStack.pop(); H, }8 w0 o3 @7 ^% k8 T7 J5 N3 {
int op1 = ((Integer)(operandStack.pop())).intValue();% F5 I' ]! I0 `0 }4 t d
int op2 = ((Integer)(operandStack.pop())).intValue();+ C' |" F3 B, z" a% i4 P+ E
operandStack.push(new Integer(op2 * op1));" D; Z1 M; Y3 s7 k- F& A8 l
}
+ M3 M9 y. R3 |9 g& o! k else if (operatorStack.peek().equals('/'))
$ O6 @ A' o% q, A( |( r { H: m9 b3 l3 ?+ R, v
operatorStack.pop();
6 {4 [9 `9 B2 P) x. r$ b4 t int op1 = ((Integer)(operandStack.pop())).intValue();5 s9 W+ c* |! B
int op2 = ((Integer)(operandStack.pop())).intValue();/ N' e1 e6 I% K! Y5 ?$ a2 P
operandStack.push(new Integer(op2 / op1));
# O; v3 p5 a( }9 b( s& k }
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" b; B! ^+ k% {. O3 k( k
4 U0 P9 ]& F$ l3 U class ImagePanel extends JPanel
2 q; w. {- ~% Q6 U( a L {
$ }& d' R4 w: ~' h) e, w2 ^% b; K public void sshow()5 `& j! j& B) D
{( ~$ r' U$ c, U
int i;+ x0 O8 l) P9 ?4 D ?1 `
for(i = 0;i < 4;i++)
2 s1 q- h9 F4 X {
9 x9 [# |: _+ t- L& x1 Q( Z* k card[i] = (int)(1 + Math.random() * 52);+ z( ?$ D; Y: Q* E+ {. m
}
9 y% e9 a; r3 g/ ?* Z) [ repaint();1 e5 `+ M: O" F! l/ w
}" s5 `6 T) D5 Y& J( N
. v0 x2 S% a6 H) m3 k$ T% Z6 @ protected void paintComponent(Graphics g)
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super.paintComponent(g);5 S0 y) q ]+ C2 e9 a5 ]9 M1 r# ~
int i;2 M! r% M& s$ x+ K: K7 u4 D
int w = getWidth() / 4;
" D2 B+ I% ?0 Y' V4 X int h = getHeight();
; i: ~8 z1 f; @; ` int x = 0;
2 o# ~0 O, d$ u' N int y = 0;; ^# ^1 _- ^& F$ n
for(i = 0;i < 4;i++)
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F( J3 O" ?5 r: f N' A: S5 F( k ImageIcon imageIcon = new ImageIcon("image/card/" + card[i] + ".png");4 v+ d& B' Q7 P/ o
Image image = imageIcon.getImage();
0 W' F$ q$ Q% ?# R6 c. j4 Z if(image != null)1 d& r+ _8 z& t X; e: k- @& \
{% V8 Y% S: j0 Z. D8 ~% E$ g
g.drawImage(image,x,y,w,h,this);0 I. y! v3 ]' E) {9 U, Q
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x += w;9 [' g# n$ H; O* b7 |& ^ f; a* ?
}
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2 `- v# e/ Y! k- U, b- N! I& L( d public static void main(String[] args)
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TwentyFourPoke_Game frame = new TwentyFourPoke_Game();
# t# Z4 N3 W6 c2 f; Z% V frame.setTitle("24 Poke Game");
8 G' R2 q% o4 _5 b4 ?5 d u frame.setLocationRelativeTo(null);
1 _: A7 Y" [3 m$ V8 y7 p, b frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
6 F2 I" R0 ?4 d S/ p frame.setSize(368,200);
2 _5 J! V. t5 s& s2 d frame.setVisible(true);
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} 复制代码
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