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给出四个数字,要求,在其间添加运算符和括号,使得计算结果等于24。
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% {- n3 ]% i( }, Y* P" b括号的放置即为决定哪几个数先进行计算。所以,我们先确定首先进行计算的两个相邻的数,计算完成后,就相当于剩下三个数字,仍需要在它们之间添加符号;然后再决定在这三个数中哪两个相邻的数先计算。由此,我们就成功解决了数字的运算次序问题,此时不需要再考虑不同运算符号的优先级问题,因为括号的优先级高于加减乘除。
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通过循环,我们可以得到第一第二第三次计算的运算符,再通过计算,就可以得出和,若和等于24,即为所求解。5 R1 i ]! b3 a" u
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在输出格式中,由于括号的放置共六种情况,故根据计算先后顺序的不同,输出时在不同地方放置括号;6 E- {, ^$ M# Q; Y$ V! H
# x8 @) I( q% _ k+ L. ^! C* |# Z以下是java源码:+ r$ z/ e: W# j2 \
- import java.awt.*;
3 W* H4 H7 c2 h2 S$ M6 S- ?0 b - import javax.swing.*;( n A) K& A, S+ K
- import java.awt.event.*;
/ \7 B: K% Q8 H* u( u$ N* K, C. B - import java.util.*;( I. v, [' a! s+ G3 ~; r
- import javax.swing.JOptionPane;
; l- ^. I4 _2 E" p7 e* o7 [ -
5 ?0 A8 C" q W! Q - public class TwentyFourPoke_Game extends JFrame7 T, M( b& l4 W5 {
- {
6 P7 q- e0 e6 p) V+ d7 l- [ - private JButton jbsolution = new JButton("Find a Solution");1 i, U; I9 [5 w6 @$ L% q1 D3 S: @, ]
- private JButton jbrefresh = new JButton("Refresh");* H+ V" v9 g/ }2 n0 w5 [) v& ~0 `
- private JButton jbverify = new JButton("Verify");
5 m8 T" X9 n4 c% q$ R( h1 A! E -
/ d) S4 E$ G& ^# i. \; Y; ] - private JLabel jlmessage = new JLabel("Enter an expression:");
8 t( \8 F" m7 h -
/ w& [% W- T/ z! H# S5 }" k- ~' } - private JTextField jtsolution = new JTextField();" g0 N) U0 p+ G) f
- private JTextField jtexpression = new JTextField();
/ z' f1 f/ \* X8 ~ - : w" q% ~8 i9 i
- private ImagePanel pp = new ImagePanel();. j/ @# M9 k. H
-
! l9 I0 r" _. K+ G& n - private int[] card = new int[4];0 p" Q4 `" L9 G
- private double[] bcard = new double[4];% F' d+ d# G2 M$ m/ c
- h% n: s1 D: A
- private double sum;3 I8 M; m/ u/ m0 y W6 X" {, }
- private double[] temp1 = new double[3];
3 n3 L2 J/ ?+ i1 e n1 ?) } - private double[] temp2 = new double[2];
6 q! @+ v" u6 y6 ? - private char[] sign = {'+','-','*','/'};' ~* J: y$ l' S& T
-
% p9 T% b8 z/ C9 T. Y - ( i& L T- r$ O* [; \8 x) F
- public TwentyFourPoke_Game()2 q2 [/ M7 c# v. z+ o h
- {
1 S' [ g( I, Z; U* B - JPanel p1 = new JPanel(new GridLayout(1,3));
! a7 H5 B/ z/ B! ^. ?5 r" H - p1.add(jbsolution);
4 V1 L9 l! a ~. N0 ^4 h: M - p1.add(jtsolution);
1 X" O* Q1 Y7 \3 |& y/ M/ m4 T) |. H - p1.add(jbrefresh);
- S- }) y. d* k9 D& W( Z - JPanel p3 = new JPanel(new GridLayout(1,3));
9 O+ Y3 H4 V9 @ - p3.add(jlmessage);
/ n) s4 a$ P6 x" N3 w - p3.add(jtexpression);
- G# \# F9 h" @1 I7 @ - p3.add(jbverify);
8 H8 s0 d1 d( f. m2 z/ i- T! S! p - * x! ^0 X8 P2 w2 g6 B0 o
- add(p1,BorderLayout.NORTH);
) n+ A1 i; L! A- p - add(pp,BorderLayout.CENTER);
* @$ j1 {2 a9 K, U+ N) k/ D - add(p3,BorderLayout.SOUTH);7 p6 p, J& w4 \+ g
-
3 W4 ^: j& u. h x O. @# o6 j - ButtonListener listener = new ButtonListener();% ^, h; f7 n ?, G( T
- jbsolution.addActionListener(listener);
7 j7 E |- w$ \ - jbrefresh.addActionListener(listener);7 x5 ~( y) H% }, a9 d
- jbverify.addActionListener(listener); z; u! M$ B8 u" @8 K
- }
( H6 @- Y( Z, f9 @9 |- L -
, M7 K- y( V* {( o" a0 k - class ButtonListener implements ActionListener' A; P( y" V) R9 |; v
- {
% H4 U) _+ T$ _ - public void actionPerformed(ActionEvent e)
9 g& M6 L( O: E7 E9 I - {
$ k' |9 `. V/ _ - if(e.getSource() == jbsolution)
4 V& w- Z3 z- z" o P" [( a, o - {
) j9 v* J- S t - for(int i = 0;i < 4;i++)% k2 p$ d; E w
- {
8 B ?, Y5 E7 W( O - bcard[i] = (double)card[i] % 13;0 \2 X5 ^ B2 j9 c1 @
- if(card[i] % 13 == 0)
. G% G+ D" r; f( O7 F& ~ - bcard[i] = 13;- b3 \8 y( m v) C& q& x4 C
- }- p4 o, v: M: Y3 x
- search(); r4 |: i |) k' G! F+ \- b
- }7 b4 H2 s! j. ^" N- Q+ f- N @$ a
- else if(e.getSource() == jbrefresh)
" I$ X8 u) @) ?4 n% U4 T# Q) z - {" ]1 r: [9 q; ]& ^! F: |" C
- pp.sshow();
. Z% ]1 }3 n8 A. ^ - " Z) R! y# a) H- E0 E
- }
7 I' c' J: K" t# f$ [ - else if(e.getSource() == jbverify)* h8 z1 q- X6 j+ \: ]3 W
- {
3 U3 ]- \- z3 a3 O$ K& f( j& p$ A: X - String expression = jtexpression.getText();1 F3 q% D' F* F$ l
- int result = evaluateExpression(expression);4 d4 U! X1 v5 `# E- U
- if(result == 24)
" L; B* D( b* k: F/ J - {/ C, t) e+ J( ?# K m& J/ g
- JOptionPane.showMessageDialog(null,"恭喜你!你答对了!","消息框",JOptionPane.INFORMATION_MESSAGE);- {5 ?. a0 k& S5 ]# y& d ]3 l
- }+ X; ?# o+ X' _ p! M) j7 Y
- else
" s7 E: c" T$ h* u7 w" R - {
9 b5 E# R# {8 q. t( f - JOptionPane.showMessageDialog(null,"抱歉!请再次尝试。","消息框",JOptionPane.INFORMATION_MESSAGE);
; U5 N. k: b3 e3 D! D - }. n7 }0 k: u- B: @+ e# R# {
- }
7 W0 F8 \* I+ P' W1 e - }- A: S8 L9 ?3 \3 q4 z: F" H _
- }
6 X: K: O7 U& s D/ }& D# z8 k -
0 Q3 d9 h% |/ i, P! R! \2 h& f - public static double calcute(double a,double b,char c)! _" d: h! ^- N/ n: }% Q1 d9 t
- {0 w+ n# i6 q. k% n. `9 N
- if(c == '+')2 `4 L. C4 Y [3 t/ g( T* e* p" M& U
- return a+b;
* e# Z1 \- V. Y& \* C - else if(c == '-')
" b/ y: B* Y# l6 Q( a/ A - return a-b;/ A0 o/ t% u, t! `
- else if(c == '*')$ D$ v' y. i8 D2 w9 v
- return a*b;; i+ u" i9 [8 @3 R
- else if(c == '/' && b != 0): y" w( ~% r$ K5 m
- return a/b;
4 `" R2 m, F3 ?5 w - else0 `! V2 r# d+ M! l5 _
- return -1;* e1 h# K/ w: q
- }
* M. V. q7 F* [' D' K7 i -
. B G& C \# Y( E5 G - public void search(). F) Y: W! C1 e7 a8 Q3 j# m7 J
- {
7 A6 q! M" L! } x" g9 a - boolean judge = false;+ b4 D% l) S/ Z
- for(int i=0;i<4;i++)+ Y1 c: q' M$ K( r# y! o0 a1 E
- //第一次放置的符号
6 m' @4 n+ ^) Y8 N - {0 |; t( F1 }3 N3 o9 U* ^6 e/ n5 x
- for(int j=0;j<4;j++)/ D& r( t8 X- ?5 T
- //第二次放置的符号: [1 R5 E v. n
- {& {4 h* S$ h* ], }/ s' ]% \
- for(int k=0;k<4;k++)
% x& v6 O, C4 W+ B: C! `) b! L6 \# u - //第三次放置的符号; b: C# f* `4 k% F# P# |
- {
. Q2 _: u: C- R( W+ u7 e - for(int m=0;m<3;m++)
$ p7 m; Y: j. c& @' j, E - //首先计算的两个相邻数字,共有3种情况,相当于括号的作用
+ G/ U6 X& B% q; q& t - {
9 Z) b( V: e* E4 o+ ` - if(bcard[m+1]==0 && sign[i]=='/') break;
, o3 m* n: ^. F! s$ J - temp1[m]=calcute(bcard[m],bcard[m+1],sign[i]);
3 F4 K9 u2 w. F( e - temp1[(m+1)%3]=bcard[(m+2)%4];
7 I3 I0 P, w( j3 x - temp1[(m+2)%3]=bcard[(m+3)%4];$ H: h4 O& [/ m8 G/ j" c# k5 P
- //先确定首先计算的两个数字,计算完成相当于剩下三个数,按顺序储存在temp数组中; j3 `. `* H' r8 ]' i3 G
- for(int n=0;n<2;n++)
& O5 H* }' w5 X: H$ H - //三个数字选出先计算的两个相邻数字,两种情况,相当于第二个括号4 h0 C" Y* Y! ]
- {
Y: s% r _ K! ?2 x2 w - if(temp1[n+1]==0 && sign[j]=='/') break;
E4 G2 j, z( i: T6 O - temp2[n]=calcute(temp1[n],temp1[n+1],sign[j]);
( ?% H# ^# s: f1 Z0 I4 V - temp2[(n+1)%2]=temp1[(n+2)%3];
. X* L8 |7 q, }- o4 ` - //先确定首先计算的两个数字,计算完成相当于剩下两个数,按顺序储存在temp数组中1 l8 U6 m7 \ E/ V
- if(temp2[1]==0 && sign[k]=='/') break;) Q- _5 F& ?/ }9 Q8 f, k
- sum=calcute(temp2[0],temp2[1],sign[k]); m5 a# c/ G0 a. ^( Y9 m
- //计算和
3 C/ l. b5 P' V+ c - if(sum==24)( \- [* B3 _ h1 e/ j8 k! c: W
- //若和为24; Q- f9 m6 |& q% W6 H7 y0 j
- {
: W, O6 Q/ g- o9 H3 ] - judge=true;* t& L8 H) A4 Z% l; O
- //判断符为1,表示已求得解
p8 p0 F% T4 y, q; D1 A8 z8 D - if(m==0 && n==0)4 t; R, u6 y: E1 ]; N
- {. `% L9 i3 [0 n3 Y: n
- String sss ="(("+(int)bcard[0]+sign[i]+(int)bcard[1]+")"+sign[j]+(int)bcard[2]+")"+sign[k]+(int)bcard[3]+"="+(int)sum;
1 w# U1 v3 ?, ~- F2 I - jtsolution.setText(sss);+ W( ^ M1 y" P2 ?7 a
- return ;6 N% Q) n" S$ F' y1 P3 J
- }: v4 f' b$ k+ K( T
- else if(m==0 && n==1)9 x+ ` V( f$ |: Q
- {
5 B2 W0 l( v, W# C! s - String sss ="("+(int)bcard[0]+sign[i]+(int)bcard[1]+")"+sign[k]+"("+(int)bcard[2]+sign[j]+(int)bcard[3]+")="+(int)sum;
2 V5 ~, O: y+ { - jtsolution.setText(sss);' p' O( |' ^) H- P8 e M2 h [
- return ;9 E# S/ q6 e& P0 \- g0 t6 b
- }
' _- u- u9 |- I4 K9 M1 |; K - else if(m==1 && n==0)
" V0 s% i X7 p* F% I - {6 c: E2 ~/ D- ]: B& z" ^
- String sss ="("+(int)bcard[0]+sign[j]+"("+(int)bcard[1]+sign[i]+(int)bcard[2]+"))"+sign[k]+(int)bcard[3]+"="+(int)sum;
7 w; R! ^# s+ v5 f5 W8 H8 `3 l' \ - jtsolution.setText(sss);' v& C1 X9 P& P$ @# H; P
- return ;( n+ f2 a, B) O$ ]5 r4 C" ~
- }& i: Q! u: `: {9 A
- else if(m==2 && n==0)/ V. @. c8 i2 h; f8 Y Z4 J
- {0 L; x+ \2 }8 A" `
- String sss ="("+(int)bcard[0]+sign[j]+(int)bcard[1]+")"+sign[k]+"("+(int)bcard[2]+sign[i]+(int)bcard[3]+")="+(int)sum;9 r" m$ c6 J& U0 ^- K5 i( o
- jtsolution.setText(sss);
, o1 n- G" `3 F* R6 d2 a - return ;
; s# s9 H: D/ V4 A& M- Z - }
V! \- a/ T% @ t& R - else if(m==2 && n==0) i7 A I5 B; @. K
- {# T0 |# Q3 W- o) k/ c$ z
- String sss =(int)bcard[0]+sign[k]+"("+(int)bcard[1]+sign[j]+"("+(int)bcard[2]+sign[i]+(int)bcard[3]+"))="+(int)sum;5 [9 s& d/ a6 ]7 R! n/ U% K
- jtsolution.setText(sss);7 [5 s3 F B9 Q5 a" Q, E/ Q
- return ;! D' U( d" i) }! g2 Y) W( [
- }' y W* l8 Q; B2 n) B1 x% b
- //m=0,1,2 n=0,1表示六种括号放置可能,并按照这六种可能输出相应的格式的计算式
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- }
5 g2 F6 I; F, n) {) L3 S4 E2 Z# L - }- U8 |3 ]- r1 x
- }
) L+ s0 O3 N! U - }
9 d$ {) J, ?; ]. g7 i" L: F - }
& d: K7 T4 H- {, K! Z - }' j: M# \# T: }* W8 Q2 n
- if(judge==false)$ r9 z% B3 d) y/ A! c& n) t
- jtsolution.setText("No solution!");
% t6 k1 {& m5 A% D% P, R4 H3 D8 [( a4 { - //如果没有找到结果,符号位为0
* P* y& Q+ R" C7 t5 B - }+ l& _- h. V# K8 J0 e- W
-
; T# c1 s* j0 J6 m) j9 t: ]9 G' \ N -
6 h$ E5 w! }5 j - public static int evaluateExpression(String expression)
. g2 E" O+ H$ I - {
: a6 P/ G3 w* U6 q9 w' M/ s+ f - // Create operandStack to store operands
3 T S# E9 r0 q( L( n - java.util.Stack operandStack = new java.util.Stack();% L+ ~8 q3 W. ]4 f- ^
- . V8 L; d7 g3 E2 F Q3 Q0 }
- // Create operatorStack to store operators
* h4 I; n% K4 V0 L- v# y7 b! u! @ - java.util.Stack operatorStack = new java.util.Stack();
9 x* n/ z$ C6 l" m. f - $ |' N4 L+ @ j: \
- // Extract operands and operators
! L( u3 ?2 ?& g - java.util.StringTokenizer tokens = new java.util.StringTokenizer(expression, "()+-/*", true);* }9 ^' b' g! K. R' R1 c9 K* e
-
9 W9 S W5 i2 ?& G7 F. _ - // Phase 1: Scan tokens% ^4 T$ ^ X/ q3 r' B3 t. |
- while (tokens.hasMoreTokens())
/ Q& M- ]2 I3 ~/ X0 e/ w - {4 W5 b, U* |6 }$ q
- String token = tokens.nextToken().trim(); // Extract a token/ w+ J5 f0 P6 \1 P7 f7 W( v. q
- if (token.length() == 0) // Blank space
& W$ @( t y7 G/ n3 \5 i - continue; // Back to the while loop to extract the next token# B- N% C% S$ k2 W
- else if (token.charAt(0) == '+' || token.charAt(0) == '-')1 T& Q6 `) o0 }
- {
( q2 y1 K; `$ v( }) d7 N - // Process all +, -, *, / in the top of the operator stack
7 R, {- V; V5 g* j$ w6 B* | - while (!operatorStack.isEmpty() &&(operatorStack.peek().equals('+') ||operatorStack.peek().equals('-') || operatorStack.peek().equals('*') ||
5 ^" [; I& @+ T! t+ O7 k - operatorStack.peek().equals('/')))
6 y2 z7 i H/ H) Q4 T - {4 s' ^5 X; H, p' E, l1 i2 [! b/ ~- V0 _
- processAnOperator(operandStack, operatorStack);! r3 Z/ s0 M- ~
- }
/ b. H$ U, w/ p9 U( Q+ H - // Push the + or - operator into the operator stack* r7 F4 a3 e) D0 x' Y
- operatorStack.push(new Character(token.charAt(0)));
: a# `$ w3 p8 `; d: u - }
5 L" t5 x6 {& j* d - else if (token.charAt(0) == '*' || token.charAt(0) == '/')
/ g* U2 {* ?7 ]' T - {
6 I2 o5 D) ]; @ y6 I1 { - // Process all *, / in the top of the operator stack
' ^4 S0 C6 ^1 |9 `1 R - while (!operatorStack.isEmpty() && (operatorStack.peek().equals('*') || operatorStack.peek().equals('/')))
* t2 I1 L( [: M - {
8 x( J/ O b7 ~" c& D# B! `1 D - processAnOperator(operandStack, operatorStack);8 q: e/ o Q# k; u7 z
- }' P- F( t' U) o
- 9 l6 O" z! M6 r8 H' z( H, T
- // Push the * or / operator into the operator stack
$ `$ d$ h$ O$ E- `; `! H - operatorStack.push(new Character(token.charAt(0)));
5 ^" o0 r) t7 W - }- Y$ v+ G6 U; M/ H
- else if (token.trim().charAt(0) == '(')/ Z" v0 C8 W7 ^" P" A
- {
; X; L: R4 N' [ - operatorStack.push(new Character('(')); // Push '(' to stack
- F. `- [' N4 c3 v# `# c - }7 N, [" G t+ f
- else if (token.trim().charAt(0) == ')'): X* j y. R1 o8 t6 M
- {( g8 i* d( C$ E5 X' h! C f
- // Process all the operators in the stack until seeing '('
; S5 m7 D- H0 a9 {& @0 `+ Z; }; D - while (!operatorStack.peek().equals('('))
7 _. }& k5 Q d - {. o) ?2 B. h" Z4 a% N
- processAnOperator(operandStack, operatorStack);* R' b8 z4 ]3 p% g5 W
- }
. p, n' d% ?, y5 Q - operatorStack.pop(); // Pop the '(' symbol from the stack ]$ n1 W4 D. I. Y
- }! @' \( Q# o& o% c4 G2 [' W
- else0 h7 Y1 a$ p+ X( `+ x4 b$ i: v F' }
- {
/ g# x/ T! D, _8 }; P3 X& B1 M - // An operand scanned
9 P" I* c. X% r - // Push an operand to the stack4 O8 i0 U3 b8 N' t5 ~" [+ C
- operandStack.push(new Integer(token)); I5 N0 Z& T0 k4 s4 W
- }% G6 f/ c1 B7 M/ a$ B v
- }2 X* G& d y, J( |, N0 a9 F G5 ?$ u( L2 E
- & ~7 n7 b# ~9 y3 R- y
- // Phase 2: process all the remaining operators in the stack
! z( _$ g1 g* @+ k# Z - while (!operatorStack.isEmpty()) }- n( O" O0 b
- {
. y1 }3 U: j: N0 H4 d: `: g - processAnOperator(operandStack, operatorStack);
, S7 _! f+ p. M) w - }9 W7 Z3 @9 q( n7 e; C+ z
- 6 V9 ?; I; `6 Y+ z4 O
- // Return the result
( T9 w w+ `5 P; L - return ((Integer)(operandStack.pop())).intValue();
2 t( K. r A' N* O4 j - }
( s: M/ \/ p$ D3 }2 {% ~& j, i! D) { -
[ Z' O* i) ?+ K) P5 j - public static void processAnOperator(java.util.Stack operandStack,java.util.Stack operatorStack)! y) n5 U) ?8 P$ g8 F
- {9 V: d s l, W8 h6 Q) x3 [0 H
- if (operatorStack.peek().equals('+'))' x1 Q1 t# D' @7 @" b/ L& y! E' |! E' k
- {( A# i# w2 y9 B5 H- a% A# i. z+ H
- operatorStack.pop();# P, B0 z0 {7 O7 _1 P: F% \
- int op1 = ((Integer)(operandStack.pop())).intValue();
" Z- p1 r. E) ~9 W. L5 H - int op2 = ((Integer)(operandStack.pop())).intValue();
6 ~$ |6 b/ v3 S$ w2 M - operandStack.push(new Integer(op2 + op1));
+ ~" k- Y6 S" g% u6 B7 w - }$ [: b4 x' H% [/ [0 D
- else if (operatorStack.peek().equals('-'))# U) f" E7 v4 Y1 @: I4 h
- {8 Q# g3 x+ P' Y) E/ E' m
- operatorStack.pop();
1 f1 O; [4 S9 @0 m w7 _% P, V - int op1 = ((Integer)(operandStack.pop())).intValue(); k: ^+ z7 f, j9 [2 `4 Q
- int op2 = ((Integer)(operandStack.pop())).intValue();7 e0 `; S+ N" {
- operandStack.push(new Integer(op2 - op1));
3 a0 \; e# w$ [" G - }+ g7 O3 l8 N* A) p+ O7 J4 G
- else if (operatorStack.peek().equals('*'))
) @9 F, {) Q* m4 q - {
E5 ]( y/ v! g6 [ - operatorStack.pop();* h! R1 {$ {# t! a' G
- int op1 = ((Integer)(operandStack.pop())).intValue();
7 y% r6 S0 }' H2 t - int op2 = ((Integer)(operandStack.pop())).intValue();
[8 Y- n9 m, z. Z - operandStack.push(new Integer(op2 * op1));7 `; {; q6 |- p
- }
! E5 Y2 k1 b$ Z) o9 k1 H d* O9 Z - else if (operatorStack.peek().equals('/'))
5 s% Y) g3 }/ K: V1 M - {
* [' j( J2 r7 B6 C: R - operatorStack.pop();
/ g& E. [0 A( `8 ~: U4 f; v - int op1 = ((Integer)(operandStack.pop())).intValue();
* e7 m$ C$ f, z$ i( V c - int op2 = ((Integer)(operandStack.pop())).intValue();: h* v5 D) L; q1 w' j r
- operandStack.push(new Integer(op2 / op1));% U% s; G) J0 N3 M) y3 N6 Z; k7 y' A
- }
l* N- S" E& D; P7 s. n; k - }
- M- z! D" o/ N+ d -
1 m5 b+ Q+ _) m7 ?2 J4 b* S- O. N% | - class ImagePanel extends JPanel
6 d# v3 |- M' @" p - {
. x! E' f. e; M m - public void sshow()
) S. b/ m% D5 V7 a - {* ?3 i ^- Y( h0 C8 Y/ P
- int i; b" u/ u, h7 F% Z) B& c' k, s6 }
- for(i = 0;i < 4;i++)/ [1 a7 z: h& @& ?1 D% i9 O7 c: Y N
- {: e* Y7 X7 J9 Q A
- card[i] = (int)(1 + Math.random() * 52);# _) a( N" l- J
- }
8 {$ p# t. S8 l. @/ L! {4 C! R+ G - repaint();6 }2 j& a8 j1 P" ~: @ g
- }
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- protected void paintComponent(Graphics g)
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4 z1 T0 y \( o - super.paintComponent(g);
- q8 s( `: l; a0 h2 E0 ] w1 y - int i;
% a4 G6 }# C1 c& {" w, ^0 n6 Y/ F - int w = getWidth() / 4;
4 T" a, o$ p9 H8 u# r6 O - int h = getHeight();; a' x% p) p3 p$ P6 t
- int x = 0;
/ M. m5 B' h' Y - int y = 0;
2 y! d7 g- N' q - for(i = 0;i < 4;i++)
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- ImageIcon imageIcon = new ImageIcon("image/card/" + card[i] + ".png");
) c/ F$ q3 O6 w/ \( d( Y F6 d8 Q+ @9 ? - Image image = imageIcon.getImage();0 t/ ~& u; E- M% g/ A) r5 m1 F
- if(image != null)0 y2 T6 y. \1 `4 G+ K4 I% {" b
- {" n6 }$ { F& x1 q- P4 ]5 r7 C
- g.drawImage(image,x,y,w,h,this);( n! V$ H* u- J3 S& @, L
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- x += w;! j( {, ~4 m! G: \2 I& o
- }
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- }
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- public static void main(String[] args)
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) w0 H$ i2 t( ?! I - TwentyFourPoke_Game frame = new TwentyFourPoke_Game();
% R; i4 X+ F7 A! O( T - frame.setTitle("24 Poke Game");
. p) }! ]2 K( b0 w - frame.setLocationRelativeTo(null);
: B4 ~" Q5 D0 f2 x. ?! I6 `4 k - frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
$ E& X0 S* w' Q - frame.setSize(368,200);
: R! T% V: ~- R' e - frame.setVisible(true);6 \( s4 }+ r, s/ i
- }* r: T# Z9 P( t
- }
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